find the times "t" during the illness at which the patients temperature was 103

Question

assume that the temperature "T" in degrees Fahrenheit, of a patient "t" days into a 12 day illness is given by :

T(t) = (101.4degreesF) + [6degreesF Sin (x/8t)]

Answer 1

T(t) = 101 + 6sin(pi/8t)

103 = 101 _ 6sin(pi/8t)

2 = 6sin(pi/8t)

sin(pi/8t) = 1/3

pi/8t = arcsin(1/3)

8t = pi/arcsin(1/3)

t = (1/8)pi/arcsin(1/3) = about .0202 days

then an infinite number of other days as temperature oscillates up and down past 103