If the molar mass of nicotine is 162.3g/mol, what is its molecular formula?

Question

The empirical formula for nicotine is C5H7N if that is of any assistance.

Answer 1

C_{5 =} 60

H₇ = 7

N = 14

Total molar mass of empirical = 81 g/mol

162.3/81 = 2 empirical formulae in the molecular formula

Molecular formula = C₁₀H₁₄N₂