These can all be treated as binomial probability problems with probability of green = p = .15 and the probability of "not green" = .85. The sample size is too small to use the normal approximation to the binomial so that you will have to compute exact binomial probabilities (or get them from a table).
Emma L.
asked 11/15/18statistics and probabilty
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select six peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)
Compute the probability that exactly five of the six M&M’s are green.
Compute the probability that four or five of the six M&M’s are green.
Compute the probability that at most five of the six M&M’s are green.
Compute the probability that at least five of the six M&M’s are green.
If you repeatedly select random samples of six peanut M&M’s, on average how many do you expect to be green? (Round your answer to two decimal places.)
green M&M’s
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