Inactive Tutor answered 03/04/20
Volume = 2 = x2y
and y=2/x2
Surface area = 2x2 +4xy = 2x2 +2/x2
take the derivative and set it equal to zero, then solve for x
to minimize surface area
4x -4/x3 = 0 multiply by x cubed
4x4 -4 = 0
x4 = 1
x= 1
y=2
Erik K.
asked 11/13/18(a) Find the dimensions x, y for which the volume is 2 and the surface area is as small as possible.
(b) Find the dimensions for which the surface area is 7 and the volume is as large as possible.
Inactive Tutor answered 03/04/20
Volume = 2 = x2y
and y=2/x2
Surface area = 2x2 +4xy = 2x2 +2/x2
take the derivative and set it equal to zero, then solve for x
to minimize surface area
4x -4/x3 = 0 multiply by x cubed
4x4 -4 = 0
x4 = 1
x= 1
y=2
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.