Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8)

Answer 1

Greetings! Lets solve this shall we ?

So, we must find an equation of a line using the given information such that the perpendicular slope must be the inverse of the given slope m = -1/-0.3 = 3.3

y - y1 = m(x - x1)

y - (-8) = 3.3(x - 3).........Then distribute such that

y + 8 = 3.3x - 10..........Then subtract 8 to both sides such that

y = 3.3x - 18

I hope this helped!