If a = (0,0) and b = (2,5) what is the approximate length of ab?

Answer 1

Use the formula for the distance between two points: d = √((x₂ – x₁)² + (y₂ – y₁²))

d = √((5 – 0)² + (2 – 0)²

d = √(25 + 4) = √(29) ≈ 5.385

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Answer 2

These points form a right triangle.

2^2 + 5^2 = AB^2

4 + 25 = AB^2

29 = AB^2

AB = √29