J.R. S. answered 11/08/18
Ph.D. University Professor with 10+ years Tutoring Experience
Recall that pH + pOH = 14
pH = 14 - pOH = 14 - 8.20
pH = 5.80
Since pH = -log [H3O+], then [H3O+] = 1x10-5.80
Written another way, [H3O+] = 1.58x10-6 M
Done another way:
pOH = 8.20
[OH-] = 1x10-8.20
[OH-] = 6.31x10-9 M
[H3O+][OH-] = 1x10-14
[H3O+] = 1x10-14/6.31x10-9
[H3O+] = 1.58x10-6 M