Write x as the number of red socks.
Write 6 − x as the number of blue socks.
Establish the probability of pulling 2 red
socks in 2 blind draws as x/6 times
(x − 1)/5 or (x2 − x)/30 equal to 2/3.
Then 3(x2 − x) = 60 or x2 − x = 20.
Now x2 − x − 20 = 0 or (x − 5) × (x + 4) = 0.
Discard x = -4 as a solution and take the
number of red socks as x = 5.
This would force the number of blue socks
to 1, giving the probability of extracting a
blue pair in only 2 blind draws as zero.