Annie X.

asked • 11/05/18

what is the value of (d-1)(e-1)?

Let d and e denote the solutions of 2x^2 +3x-5=0


a)-5/2

b)0

c)3

d)5

e)6

Samuel B.

First, find the solutions of 2x^2 +3x-5=0. x^2 + 3x - 10 = 0 (2) (x+5)(x-2) = 0 (2) (2x+5)(x-1) = 0 x = -5/2, 1 Let d = -5/2, and e = 1 (-5/2 - 1)(1 - 1) --> 0... The answer is B.
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11/05/18

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