J.R. S. answered 10/31/18
Ph.D. University Professor with 10+ years Tutoring Experience
MCO3 + 2HX ==> MX2 + H2O + CO2
Molar mass of CO2 = 44 g/mole
44 g / molar mass of unknown = 0.30
molar mass of unknown = 44/0.30
molar mass of unknown = 147
MCO3 = 147 and CO3 = 60 g/mol
Thus M = 147 - 60 = 87
This atomic weight is consistent with strontium or Sr, so answer appears to be (B) Sr2+