Let L = length, W = width and P = perimeter
L = 3W
P = 86 = 2(L + W)
Anisah M.
asked 10/30/18Let L = length, W = width and P = perimeter
L = 3W
P = 86 = 2(L + W)
Victoria V. answered 10/30/18
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
Perimeter is the distance around the outer edge of the rectangle.
The rectangle has 2 lengths (L) and 2 widths (W), so the perimeter equation is
P=2L + 2W =86
divide both sides, everything on both sides, by 2, and one of your equations in the system of equations is
L + W = 43
The other is that the length (L) is (=) triple (3 times) the width (W).
In math-speak, this other equation for your system of equations is
L=3W
Then can substitute L=3W into the "L" in L+W=43,
then solve for W,
multiply your answer for W by 3 and get L
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