If the pressure of 25.0 mL of air is 0.750 atm, what would the pressure be if you increased the volume to 55.0 mL

Answer 1

Assuming constant temperature, you have the relationship of P1V1 = P2V2 (see Boyles Law).

P1 = 0.750 atm

V1 = 25.0 ml

P2 = ?

V2 = 55.0 ml

(0.750(25.0 ml) = (P2)(55.0 ml)

P2 = (0.750)(25.0)/55.0

P2 = 0.341 atm (to 3 sig.figs.)