J.R. S. answered 10/25/18
Ph.D. University Professor with 10+ years Tutoring Experience
(5.60x10^6 J) / (30.8 J/K*mol) / 10.0 K = 18182 moles Na
18,182 moles Na x 22.99 g/mole = 4.18x10^5 g Na
Erica C.
asked 10/25/18Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 5.60 MJ of energy (in the form of heat) if the temperature of the sodium is not to increase by more than 10.0C? Use Cp = 30.8 J/(K*mol) for Na(l) at 500K.
_???__ g
J.R. S. answered 10/25/18
Ph.D. University Professor with 10+ years Tutoring Experience
(5.60x10^6 J) / (30.8 J/K*mol) / 10.0 K = 18182 moles Na
18,182 moles Na x 22.99 g/mole = 4.18x10^5 g Na
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.