I am not aware of any identity which will help solve this problem.
A graph will give you an approximate root and if your graphing calculator is sophisticated, it will solve the problem for you. Mine gave 2.267172.
However, there are 3 additional comments which may be helpful.
If you expand sin in a Taylor's series, the first approximation to a root is x^3 = 90, i.e. x = 2.08.
Newton's method can be used (if you don't know the formula, look it up!). I used 2.08 as a first approximation and got 2.227 as my 2nd approximation.
Lastly, you can also use interval halving starting from 2 pi/3 and 3pi/4 which you can see from a graph.