A rubber super willll pop off if the pressure exceeds 1.25 atm. If the pressure is 0.985 atm when the volume is 295 ml, at what volume will the stopper pop off?

Answer 1

If the temperature remains constant, then P1V1 = P2V2

(0.985 atm)(295 ml) = (1.25 atm)(V2)

Solve for V2

(note: Review Boyles Law)