Elijah P.
asked • 10/21/18How many grams of NH3 can be produced from 4.16 mol of N2 and excess H2.
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1 Expert Answer
J.R. S. answered • 10/21/18
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
Balanced equation:
N2 + 3H2 ==> 2NH3
4.16 mol N2 x 2 mol NH3/mol N2 = 8.32 moles NH3
8.32 moles NH3 x 17 g/ mole = 141 g NH3
J.R. S.
tutor
Do 2nd question in a similar fashion using same stoichiometry. Convert g H2 to moles, then find moles NH3, then conert to molecules using Avogadro’s number.
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10/21/18
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Elijah P.
How many molecules (not moles) of NH3 are produced from 7.92×10−4 g of H2?10/21/18