J.R. S. answered 10/17/18
Ph.D. University Professor with 10+ years Tutoring Experience
11.3 g H2O/25.0 g total = 0.452 = 45.2% H2O
Brian M.
asked 10/17/18Cobalt (II) chloride is commonly obtained from chemical supply houses as a hydrate with the formula CoCl2* 6 H2O. An analysis showed that 25.0 g of this hydrate contains 11.3 g of water. What is the percent water by weight in this hydrate?
J.R. S. answered 10/17/18
Ph.D. University Professor with 10+ years Tutoring Experience
11.3 g H2O/25.0 g total = 0.452 = 45.2% H2O
Tesfaye D. answered 10/17/18
PhD in Chemistry with Research and Teaching Experiences
Hi Brian, you can calculate the percent water by using:
Percent of water = (mass of water/mass of hydrate ) x100
= (11.3 g/25.0g) x 100
= 45.2%.
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