For the following equations, calculate the mass of Fe2O3 needed to produce 45.3 g CO Fe2O3 + 3C → 2Fe + 3CO

Question

For the following equations, calculate the mass of Fe₂O₃ needed to produce 45.3 g CO

       Fe₂O₃ + 3C → 2Fe + 3CO

Answer 1

Fe₂O₃ + 3C → 2Fe + 3CO .. balanced equation

Work in moles, not in grams.

Moles of CO desired = 45.3 g CO x 1 mole/28 g = 1.618 moles desired

From the balanced equation, how many moles of Fe2O3 would be required? It takes 1 mole Fe2O3 to make 3 moles of CO (see balanced equation). Thus, ...

1.618 moles CO x 1 mole Fe2O3/3 moles CO = 0.5393 moles Fe2O3 needed

Now, you can convert this to grams:

0.5393 g Fe2O3 x 159.7 g/mole = 86.1 g Fe2O3 needed (to 3 sig. figs.)

Answer 2

  Fe₂O₃ + 3C → 2Fe + 3CO

45.3 g CO x (1 mole CO/28.01 g CO) x (1 mol Fe2O3/3 mol CO) x (159.69 g Fe2O3/1 mol Fe2O3) = ?

Solve this for your answer.

Answer 3

 Fe₂O₃ + 3C → 2Fe + 3CO

this is the balanced equation from which the mole ratio/s can be derived.

45.3 g CO x (1 mole CO/28.01 g CO) x (1mole  Fe₂O₃/3 mole CO) x (159.69 g Fe2O3/ 1 mole Fe2O3) = ?

Solve this for the answer.

Answer 4

Fe₂O₃ + 3C → 2Fe + 3CO .. balanced equation

How many moles is 45.3 g of CO?

45.3 g x 1 mole/28 g = 1.618 moles CO

From the balanced equation, how many moles of Fe2O3 are needed?

1.618 moles of CO x 1 mole Fe2O3/3 moles CO = 0.539 moles Fe2O3 needed (assuming C is in excess)

mass of Fe2O3 needed = 0.539 moles Fe2O3 x 160 g/mole = 86.3 g Fe2O3 needed