For the following equations, calculate the mass of NO produced from 32.0 g NH3 4NH3 + 5O2 → 4NO + 6H2O

Question

For the following equations, calculate the mass of NO produced from 32.0 g NH₃     

          4NH₃ + 5O₂ → 4NO + 6H₂O

Answer 1

4NH₃ + 5O₂ → 4NO + 6H₂O .. balanced equation

32.0 g NH3 x 1 mol/17 g = 1.88 moles NH3

mass of NO produced = 1.88 moles NH3 x 4 moles NO/4 moles NH3 x 30 g/mole = 56.4 g NO produced