If you combine 420.0 mL of water at 25.00 °C and 120.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

Heat lost by hot water = heat gained by cold water

(120g)(4.184J/g/deg)(Ti-Tf)= (420g)(4.184 J/g/deg)(Tf-Ti)

where Ti and Tf are initial and final temperature respectively.

Solve for Tf