5log(25-x2)-(log(5+x)+log(5-x))=log( )

Question

Using laws of logarithms, write the expression below as a single logarithm.

5log(25−x^2)−(log(5+x)+log(5−x))=log( )

Answer 1

Using log(m)+log(n)=log(m*n)

Log(m)-log(n)=log(m/n)

25-x^2=(5-x)*(5+x)

 

=log(((25-x^2)^5)*(5-x)/(5+x))

 

=log(((5-x)^6)*((5+x)^4))