Melvin H. answered • 10/13/14

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Hi Sean,

The rate of power usage (kWh/d) depends on the product of heat-loss coefficient coefficient and the temperature difference to be maintained.

dP/dt = 3.6 kWh/d/°C × (40°C - 22°C) = 64.8 kWh/d

If the question means that the house is cooled from 40° to 22°C, then with everything being linear for that period of time , dP/dt = 32.4 kWh/d since the "average" temperature difference would be 9°C