Arthur D. answered 10/09/14
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
x=the smaller angle of the parallelogram
the ratio between adjacent angles is 4:5
y=the larger angle of the parallelogram
x/y=4/5
4y=5x and y=(5/4)x
x+x+(5/4)x+(5/4)x=360
4.5x=360
45x=3600
x=80º and y=100º
one angle of a quadrilateral is twice 80º or 160º
that leaves 360º-160º=200º for the sum of the remaining three angles of the quadrilateral
the three angles are in the ratio of 4:11:9
find these three angles...
4a+11a+9a=200º
24a=200º
a=200/24
a=(8 1/3)º
the angles are 4(8 1/3)=(33 1/3)º
11(8 1/3)=(91 2/3)º
9(8 1/3)=75º
the sum of the smallest and greatest angles of the quadrilateral are:
(33 1/3)º+160º=(193 1/3)º