J.R. S. answered 10/04/18
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Reaction H2 + I2 <---> 2HI
Initial 0 0 1.00
Change +x +x -2x
Equilib x x 1.00 - 2x
K = [HI]2 / [H2][I2] = 49
49 = (1.00 - 2x)2 / (x)(x)
49 = (1.00 - 2x)2 / x2
7 = 1.00 - 2x / x
7x = 1.00 - 2x
9x = 1.00
x = 0.111
Equilibrium [HI] = 1.00 - 2x = 1.00 - 2x0.111 = 1.00 = 0.222 = 0.778 M