
Dattaprabhakar G. answered 10/04/14
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Theresa:
Step 1; Let μF be the population mean of self-worth measure for females.
Ho : μF = 30. H1 : μF ≠ 30 .
Step 2: Since the population SD is not given (unknown) t-test is to be used Characteristic (1) Degrees of Freedom (DF) = 150 - 1 = 149 Characteristic (2) Large DF, so t-distribution can be approximated as normal. Characteristic (3): Symmetric bell shaped.
Step 3: Cutoff scores (1 point): α = 0.05. Cut-off scores: plus or minus 1.96 (tα/2 = zα/2 (approx) = 1.96.)
Step 4: Calculate the statistic t = (sample mean - (null) hypothesized μF) / [Sample SD / √(sample size)]
t = (31.9 - 30) / [10.52/√150] = 2.21
Step 5: Statistical decision and interpretation
Since the calculated t is larger than the cut-of value, we reject the null hypothesis. Interpretation: The data provide sufficient evidence at 5% level of significance the the population mean of self-worth battery for adult females is different from from the corresponding mean for adult males.
Dr. G.
Theresa L.
10/05/14