J.R. S. answered 09/10/18
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If I understand you description, you have the longest continuous chain being 7 carbons, counting from the right and including the propyl group. Seven carbons is heptane, and a double bond makes it heptane. So, counting from the right, you have 4-ethyl-1-heptene.
C-C-C-C-C=C
........|
.......C-C-C
Start numbering from the right where the double bond is and when you get to C#4 go down to the propyl group number them 5, 6, 7. Then you have a 2 carbon (ethyl) group off of C#4.