
Judy M. answered 09/05/18
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Credentialed Math Teacher with 20+ Years of Experience
Let r be the team's rowing rate in calm water.
Let c be the rate of the current
When rowing with the current, the rate is r + c and we can calculate it to be (40/2) km/hr or 20 km/hr
When rowing against the current, the rate is r-c and we can calculate it to be (16/2) km/hr or 8 km/hr
Therefore the system is r + c = 20
r - c = 8
Combining the equations, 2r = 28
r = 14
Plugging back in, c = 6. You can now answer the questions.