Arturo O. answered 09/04/18
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The given equation is not correct. The height as a function of time is
h(t) = -gt2/2 + v0t + h0
g = 32 ft/s2
v0 = 60 ft/s [given]
h0 = 0 [if tossed from the ground]
h(t) = -16t2 + 60t
The flight ends when the ball reaches the ground again, so set
h(t) = 0
and solve for t.
-16t2 + 60t = 0
t(-16t + 60) = 0
The moment of tossing is
t = 0,
so the time in flight must be the solution to
-16t + 60 = 0
Solve this to get t in seconds, and finish from here.
Arturo O.
If you must work with that incorrect equation, solve for t in the same way as I explained for the correct equation.
To find maximum height, recall the maximum is at the vertex of the height-vs.-time parabola. The time at the vertex is
t = -b/(2a),
where a is the coefficient of the term with t2, and b is the coefficient of the term with t. Then evaluate h(t) at this value of t to get the maximum height.
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09/04/18
Fred J.
09/04/18