Mark M. answered 08/16/18
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Note that 28 = 33+1
So, Let's try F(x) = x3+1
Then F(x)·F(1/x) = [x3+1][(1/x)3+1]
= 1 + x3 + (1/x)3 + 1
= (1+x3) + ((1/x)3+1) = F(x) + F(1/x)
So, F(x) = x3 + 1 satisfies the given property.
For this function, F(4) = 43 + 1 = 65.
Mark M.
08/16/18