Inactive Tutor answered 08/06/18
Tutor
New to Wyzant
K(t) = 50 (0.65)t
log(K) = log50 + t log(0.65)
t = [log(K) - log50] / log(0.65)
t = [1/log(0.65)] log(K) - log50/log(0.65)
A = 1/log(0.65)
B = -log50 / log(0.65)