Let's recall the equation is [Z]= [Z]0*e-kt where [Z]0 is the initial concentration and t is time.
To make it easier on ourselves, let's do some rearranging to isolate the k:
[Z]/[Z]0= e-kt
ln([Z]/[Z]0)= -kt
- (ln([Z]/[Z]0)/t= k
From here, we can just plug and chug:
- (ln (0.1153/1))/3000= k
7.201 x 10-4= k
To double check, I like to plug the k back into the original ( [Z]= [Z]0e-kt) with the other data point:
[Z]= 1.000e-((7.201x10^-4)*900)
[Z]= 1.000*(0.5231)
[Z]= 0.5231 which is what the data shows.
So the final answer is that the rate constant k= 7.201 x 10-4
J.R. S.
07/30/18