I assume you intend the probability of correct answer in each case is 1/4.

Then the probability o 2 right answers is (1/4)*(1/4) = 1/16.

Danny P.

asked • 07/25/18A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 4 answer choices - a, b, c, d - and only one correct answer. What is the probability that he answered both of the questions correctly?

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I assume you intend the probability of correct answer in each case is 1/4.

Then the probability o 2 right answers is (1/4)*(1/4) = 1/16.

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