Mark M. answered 07/18/18
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Retired Math prof with teaching and tutoring experience in trig.
Let θ = sin-1(1+x). So, sinθ = 1+x = (1+x) / 1.
Draw a right triangle with hypotenuse 1, and side opposite acute angle θ of length 1+x.
Then, by the Pythagorean Theorem, the side adjacent to θ has length √[12 - (1+x)2] = √(-2x-x2).
So, cos(sin-1(1+x)) = cosθ = adjacent/hypotenuse = √(-2x-x2)