Need help with geometry ASAP

Question

What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
A. −3/7
B. 3/5
C. −7/3
D. 3/7

Answer 1

Hi, Aashish.

 

So let's rewrite the equation 7x-3y=10 in y = mx +b form:

3y = 7x - 10

y = (7/3)x - 10/3

So, the slope (m) is 7/3

So, you want a line that is perpendicular to 7/3, therefore it needs to be the negative reciprocal.

 

Therefore the slope must be -3/7

Answer 2

7x-3y=10

-3y=10-7x

3y=7x-10

y=(7/3)x-(10/3)

the slope of a perpendicular line is the negative reciprocal of the slope of the line it is perpendicular to

therefore, -3/7 is the slope which is C.