Kate L.

asked • 07/05/18

Mean and standard deviation

An engineer is redesigning an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. the new population of pilots as normally distributed weights with mean of 140 lb and stand deviation of 263 lb. 
If a pilot is randomly selected, find the probability that his weight is between 130 lb and 171 lb. 

1 Expert Answer

By:

Anita A. answered • 07/05/18

Tutor
4.9 (231)

college freshman statistics

Kate L.

Thank you so much Anita, you were right that was a misprint. 
I forgot to include the second part of the question, If 32 different pilots are randomly selected, find the probability that their mean weight is between 130 lb and 171 lb. 
The probabilty is approximately _____. (Round to four decimal places as needed) 
 
When redesigning the ejection seat, which probabilty is more relevant? 
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07/05/18

Anita A.

new formula
 
z= (x-μ)/(σ/√n)
 
(130-140)/(26.3/√32) = -2.15 ≈ -2.2
 
(171-140)/(26.3/√32) = .6668 ≈ .67
 
P(-2.2 < z < .67) = .0819
 
The .0819 value, though quite conservative, provides tighter security for the pilot selected.
 
I'm a bit rusty on some of this stuff, but I think these results are good.
 
aa
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07/05/18

Anita A.

new formula  z= (x-μ)/(σ/√n)
 
probability: .0819
 
Better value from the point of security, though probably more difficult to manufacture.
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07/05/18

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