Anita A. answered 07/05/18
Tutor
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college freshman statistics
Hello Kate,
I suspect that there is a misprint in the above question.
It seems more likely that the standard deviation is 26.3 lb.
Working with 26.3 rather than 263 and the formula (x - μ)/σ, the result is as follows:
P(.3530 < z < .8810) =.5290
If I work with σ = 263, the result is P( .4840 < z < >5478) = .0638.
Regards,
Anita A.
Anita A.
new formula
z= (x-μ)/(σ/√n)
(130-140)/(26.3/√32) = -2.15 ≈ -2.2
(171-140)/(26.3/√32) = .6668 ≈ .67
P(-2.2 < z < .67) = .0819
The .0819 value, though quite conservative, provides tighter security for the pilot selected.
I'm a bit rusty on some of this stuff, but I think these results are good.
aa
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07/05/18
Anita A.
new formula z= (x-μ)/(σ/√n)
probability: .0819
Better value from the point of security, though probably more difficult to manufacture.
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07/05/18
Kate L.
07/05/18