Dilution Calculation

Question

0.25 g of calcium nitrate is dissolved in 100 mL water. A 50 mL sample of this solution was diluted to 75 mL. What was the final concentration?

Answer 1

0.25 g Ca(NO3)2 x 1 mol/164 g= 0.0015 moles

0.0015 moles/0.1 L = 0.015 mol/L

0.015 mol/L x 0.05 L= 0.00075 moles

0.00075 moles/.075 L = 0.01 mol/L = 0.010 M