
Kenneth S. answered 05/24/18
Tutor
4.8
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Your equation is equivalent to -2cox x = (sin x)/(cos x)
sin x = -2cos2x
sin x = -2(1-sin2x)
2sin2x - sin x - 2 = 0
let y = sin x; then 2y2 - y - 2 = 0 has discriminant (-1)2 - 4(2)(-2) = 1 + 17 and y = (1 ±√17) / 4;
using the + sign preceding square root of 17 yields y =1.28... which cannot be any sine value, so y = (1-√17)/4
which is about -0.780776406. For this solution, there are many values x in either quadrant III or IV; if the problem requested solutions that are positive but < 360 degrees, there would be TWO solutions.