Inactive Tutor answered 05/22/18
Tutor
New to Wyzant
Suppose the race is 2D km long.
[1] D = 5t1 ... this is the first half of the distance, at 5 km/hr, taking t1 hours
[2] D = 10t2 ... this is the second haf of the total distance, at 0 km/hr, taking t2 hours.
the total time is t1 + t2 =D/5 + D/10.
the average velocity is total distance divided by total time: (2D) / [3D/10] = 20/3 = 6 2/3 km/hr.