J.R. S. answered 05/21/18
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2 kg CO2 x 1000 g/kg x 1 mol/44g = 45.5 moles of CO2
If you assume that air is 0.04% CO2, then ...
x moles of air x 0.0004 = 45.5 moles CO2
x = 113,750 moles of air
Assuming you are operating under conditions of STP, and assuming air acts as an ideal gas, then...
113,750 moles air x 22.4 liters/1 mole = 2,548,000 liters of air would be required.
This is a bizarre question, and makes several assumptions.