Mariella R.

asked • 05/11/18

Please help, I can't figure out how to solve for the freezing point.

given the one mole of particles dissolved in 1 kg of water will lower the freezing point of water by 1.86 c.of o.50 mole of nacl is added to 1.0 kg of water. the freezing point of the solution will be

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J.R. S. answered • 05/11/18

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The question is not clearly stated but I’ll assume the following. You have 0.5 moles of NaCl in 1 kg of water and you want to know the freezing point. 
Delta T = imK = (2)(0.5)(1.86) = 1.86 degrees
The new freezing point is -1.86 degrees C
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Jane M.

thank you for your help. I was wondering to make this into conversion factors. the formula would be NaCl-->Na +Cl2.  so I wrote the problem as O.50 mol NaCl X (2 mol solute particles / 1 mole NaCl) X (1.86 C / 1 mole of solute particles. I got the answer 1.86. I just wanted to clarify some things. SO the reason the answer is -1.86 is because we are trying to find the freezing point right? Also, the 2 mole of solute particles comes from Cl2, right? Or am I totally off track ? Thank you for your time, any help is appreciated greatly.
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05/11/18

J.R. S.

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No. NaCl ->Na+ +Cl-.  It DOES NOT ->Cl2. True there are 2 moles is solute particles per mole of NaCl but those are 1 Na and 1 Cl. So you are INCORRECT to say the 2 particles come from Cl2. There is 1 Cl and 1 Na for a total of 2. 
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05/11/18

Jane M.

My mistake, thank you for correcting me and helping me understand the problem more clearly. I really appreciate the help.
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05/12/18

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