if the battery is a 9-volt battery and the resistance in the circuit is 18 ohm's how much current is flowing through the circuit

Question

can someone help me with the last problems

Answer 1

Use Ohm's Law:

 

V = IR

• V = voltage = 9 volts
• I = current
• R = resistance = 18 ohms

 

V = IR

9 = I·18

 

Solve for I.

Answer 2

you want to apply Ohm's Law here

Voltage (V) = Current(I) x Resistance(R)

for this set of parameters that becomes

I = V/R = 9V / 18 ohms = 0.5A

meaning that the current flowing through the circuit is 0.5 amperes

Answer 3

If they're in series R also has 9V across it.

v=Ri  so  i=v/R=9/18=.5A