queston in description

Question

how many grams of Cr₂(CO₃₎₃ will react with 526cm³ of 1.37 M H₂SO₄?

 

Cr₂(CO₃)_{3 (aq)} + H₂SO4 (aq)   ---->  Cr₂(SO₄)_{3 (aq)}  +  CO_{2 (g)} + H₂) _(I)

 

Need help solving 

Answer 1

You MUST start with a correctly balanced equation:

Cr₂(CO₃)₃ (aq) + 3H₂SO₄ (aq) ----> Cr₂(SO₄)₃ (aq) + 3CO₂ (g) + 3H₂O (l)

moles of H₂SO₄ present = 1.37 moles/L x 0.526 L = 0.721 moles

moles Cr₂(CO₃)₃ needed = 0.721 moles H2SO4 x 1 mole Cr₂(CO₃)₃/3 moles H₂SO₄ = 0.240 moles

grams Cr₂(CO₃)₃ needed = 0.240 moles x 284 g /mole = 68.2 g