J.R. S. answered 05/09/18
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First, it is easiest to convert ºF to ºC.
5/9(F-32) = 5/9(0-32) = 5/9(-32) = - 17.8ºC
Now, for the colligative property equation for freezing point depression:
∆T = imK
∆T = change in temperature = -17.7ºC
i = van't Hoff Factor = 2 for NaCl (1Na+ and 1 Cl-)
m = molality = moles NaCl/kg water = ?
K = freezing constant for H2O = -1.86ºC/m
Solving for m: m = -17.7/(2)(-.186) = 4.78 moles/kg
Solving for moles of NaCl: 4.78 moles/Kg = x moles/0.347 kg and x = 1.66 moles NaCl
Solving for grams of NaCl: 1.66 moles x 58.4 g/mole = 96.8 g NaCl needed