Calculating mole fraction in a gas mixture

Question

A 8.00 L tank at 28.5 C is filled with 19.2 g of carbon dioxide gas and 8.08 g of carbon monoxide gas. You can assume both gasses behave as ideal gasses under these conditions. Calculate the mole fraction of each gas.

 

 

Answer 1

Moles of carbon dioxide gas = 19.2 g x 1 mole/44 g = 0.436 moles

Moles of  carbon monoxide gas = 8.08 g x 1 mole/28 g = 0.289 moles

Total moles = 0.436 + 0.289 = 0.725 moles

Mole fraction of carbon dioxide = 0.436/0.725 = 0.601

Mole fraction of carbon monoxide = 0.289/0.725 = 0.399