1/sqrt(2) = sqrt(2)/2
arccos[sqrt(2)/2] = 45°
cos(360° + 45°) = cos(405°) = cos(45°)
If 2x = 405, then x = 202.5 which is in the 3rd quadrant
I will let you look up the trig functions of that angle.
Charlotte C.
asked 05/03/18
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