How do you multiply the binomial (2c - 1) (3c - 2)

Question

How do you multiply the binomial (2c - 1) (3c - 2)

Answer 1

(2c - 1) (3c - 2)

= 2c(3c-2) - 1(3c-2)

= 2c·3c - 2c·2 - 1·3c - 1·(-2)

= 6c² - 4c - 3c + 2

= 6c² - 7c + 2