(2c - 1) (3c - 2)
= 2c(3c-2) - 1(3c-2)
= 2c·3c - 2c·2 - 1·3c - 1·(-2)
= 6c2 - 4c - 3c + 2
= 6c2 - 7c + 2
Justin H.
asked • 04/29/18How do you multiply the binomial (2c - 1) (3c - 2)
How do you multiply the binomial (2c - 1) (3c - 2)
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