the reaction

Question

In the reaction 2Mg(s) +O₂(g)+2H₂O(1)→2Mg^₂₊(aq)+4OH^-(aq) which substance is reduced, how many electrons are transferred and which substance is oxidized?

Answer 1

2Mg(s) +O2(g)+2H2O(1)→2Mg2+(aq)+4OH-(aq)

Mg goes from zero to 2+ oxidation number. It has been oxidized.

O2 goes from zero to 2- oxidation number.  It has been reduced.

2 electrons were transferred.  2Mg ==> Mg²⁺ + 2e^- and O₂ + 2e^- ==> O^2-