Guys please help me with this. Please

Question

The air consists of nitrogen (78% by volume), oxygen (21%) and Argon (1%).

A. Determine the volume occupied by 1 mole of the mixture at P = 1atm and T = 273K
B. Determine the volume occupied by each of the components of the mixture
C. Determine the volume occupied by each component of the mixture if we heat at T = 298K (P remains constant)

Answer 1

A.) Taking P=1 atm and T=273K as STP, one mole of ANY IDEAL gas = 22.4 liters.  Thus, assuming you treat air as an ideal gas the volume of 1 mole will be 22.4 liters.

B.)  N₂ = 0.78 x 22.4 = 17.4 liters;  O₂ = 0.21 x 22.4 = 4.7 liters;  Ar = 0.01x22.4 = 0.2 liters

C.)  V₁/T₁ = V₂/T₂

22.4/273 = V₂/298 and V₂ = 24.5 liters

N₂ = 0.78x24.5 = 19.1 liters;  O₂ = 0.21x24.5 = 5.1 liters;  Ar = 0.01x24.5 = 0.25 liters