calculate the molar concentration of a 40% solution (w/w) of NaOH that has a specific gravity of 1.605

Question

topic: solutions

Answer 1

40% (w/w) = 40 g/100 g = 400 g/1000g solution

1000 g soln x 1 ml/1.605 g = 623 ml of solution

molar mass NaOH =~40g/mole

400 g x 1 mol/40 g = 10 moles NaOH

10 moles/0.623 L = 16.05 moles/liter =16.1 M