what is the resulting Δtf of the solution? PLEASEEEE HELP

Question

A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point constant for water (Kf) is -1.86 °C/m, what is the resulting Δtf of the solution? Show all the steps taken to solve this problem.

 

 

 

Answer 1

The formula that you want to use for this problem is ∆T = imK where

∆T = change in freezing point

i = van't Hoff factor = 1 for glucose

m = molality of glucose = moles gluc/kg water = 23.5 g/186g/mol/0.245 kg = 0.516 molal

K = freezing constant = 1.86

∆T = (1)(0.516)(-1.86) = -0.959 degrees C  <=ANSWER